By how much is the area of rectangle (in `cm^(2)`) of sides 2 cm and 1.5 cm greater than the area of a square of side `1 cm` ?

Answer

To solve the problem, we need to find the area of the rectangle and the area of the square, and then determine how much greater the area of the rectangle is compared to the area of the square.

### Step-by-Step Solution:

1. **Calculate the Area of the Rectangle:**
- The formula for the area of a rectangle is given by:
\[ \text{Area} = \text{Length} \times \text{Breadth} \]
- Here, the length of the rectangle is 2 cm and the breadth is 1.5 cm.
- Plugging in the values:
\[ \text{Area of Rectangle} = 2 \, \text{cm} \times 1.5 \, \text{cm} = 3 \, \text{cm}^2 \]

2. **Calculate the Area of the Square:**
- The formula for the area of a square is given by:
\[ \text{Area} = \text{Side}^2 \]
- Here, the side of the square is 1 cm.
- Plugging in the value:
\[ \text{Area of Square} = 1 \, \text{cm} \times 1 \, \text{cm} = 1 \, \text{cm}^2 \]

3. **Find the Difference in Areas:**
- To find out how much greater the area of the rectangle is than the area of the square, we subtract the area of the square from the area of the rectangle:
\[ \text{Difference} = \text{Area of Rectangle} - \text{Area of Square} \]
- Plugging in the areas we calculated:
\[ \text{Difference} = 3 \, \text{cm}^2 - 1 \, \text{cm}^2 = 2 \, \text{cm}^2 \]

4. **Conclusion:**
- The area of the rectangle is 2 cm² greater than the area of the square.

### Final Answer:
The area of the rectangle is 2 cm² greater than the area of the square.

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