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Two rectangles ABCD and EFGH are congrue...

Two rectangles ABCD and EFGH are congruent.
If the length of the rectangle ABCD is 12 m and its perimeter is 40 m, find the length and breadth of rectangle EFGH.

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To solve the problem step by step, we will find the length and breadth of rectangle EFGH given that it is congruent to rectangle ABCD. ### Step-by-Step Solution: 1. **Understand the Properties of Congruent Rectangles**: - Since rectangles ABCD and EFGH are congruent, their corresponding lengths and breadths are equal. 2. **Identify the Given Information**: - Length of rectangle ABCD (L1) = 12 cm - Perimeter of rectangle ABCD = 40 cm 3. **Recall the Formula for the Perimeter of a Rectangle**: - The formula for the perimeter (P) of a rectangle is: \[ P = 2 \times (Length + Breadth) \] - We can rearrange this formula to find the breadth (B): \[ P = 2 \times (L + B) \implies B = \frac{P}{2} - L \] 4. **Substitute the Known Values into the Perimeter Formula**: - Substitute the perimeter and length into the rearranged formula: \[ 40 = 2 \times (12 + B) \] 5. **Simplify the Equation**: - Divide both sides by 2: \[ 20 = 12 + B \] 6. **Solve for the Breadth (B)**: - Subtract 12 from both sides: \[ B = 20 - 12 = 8 \text{ cm} \] 7. **Conclusion for Rectangle ABCD**: - Length (L1) = 12 cm - Breadth (B1) = 8 cm 8. **Apply Congruence to Rectangle EFGH**: - Since rectangles ABCD and EFGH are congruent: - Length of rectangle EFGH (L2) = L1 = 12 cm - Breadth of rectangle EFGH (B2) = B1 = 8 cm ### Final Answer: - Length of rectangle EFGH = 12 cm - Breadth of rectangle EFGH = 8 cm
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