Home
Class 7
MATHS
CF and AE are equal perpendiculars on BD...

CF and AE are equal perpendiculars on BD, BF = FE = ED

`DeltaABE` is congruent to

A

`DeltaAED`

B

`DeltaBFC`

C

`DeltaCDF`

D

`DeltaBCD`

Text Solution

Verified by Experts

The correct Answer is:
C
Promotional Banner

Topper's Solved these Questions

  • CONGRUENCE OF TRIANGLES

    MTG IIT JEE FOUNDATION|Exercise Subjective Problems (Very Short Answer Type)|10 Videos

  • CONGRUENCE OF TRIANGLES

    MTG IIT JEE FOUNDATION|Exercise Subjective Problems (Short Answer Type)|12 Videos

  • CONGRUENCE OF TRIANGLES

    MTG IIT JEE FOUNDATION|Exercise Assertion & Reaction Type|5 Videos

  • COMPARING QUANTITIES

    MTG IIT JEE FOUNDATION|Exercise Olympaid/HOTS Corner|20 Videos

  • DATA HANDLING

    MTG IIT JEE FOUNDATION|Exercise Olympiad / Hots Corner |20 Videos

Similar Questions

Explore conceptually related problems

CF and AE are equal perpendiculars on BD, BF = FE = ED ABCD is a

CF and AE are equal perpendiculars on BD, BF = FE = ED angleBAE= ____.

In the given figure, KK' and LL' are equal and perpendicular to AC. Show that DeltaKK'MandDeltaLL'M are congruent.

In the given figure, AB is a diameter of a circle and CD is perpendicular to AB, if AB = 10 cm and AE = 2 cm, then what is the length of ED ?

ABCD is an isosceles trapezium . bar(AB) ||bar(CD) . AE and BF are the perpendicular drawn to CD. The congruence property used to prove the congurence of triangles AED and BFC is ______

ABC is a triangle right angled at A and AD is perpendicular to BC. If BD = 8 cm and DC =12.5 cm, then what is AD equal to ?

A square metal wire loop of side 20 cm and resistance 2Omega is moved with a constant velcoity v_(0) in a uniform magnetic field of induction B = 1 Wb//m^(2) as shown in the figure. The magnetic field lines are perpendicular to the plane of the loop. The loop is connected to a network of resistance each of value 5Omega . The resistances of the lead wires BF and AE are negligible. What should be the speed of the loop, so as to have a steady current of 2 mA in the loop? Give the direction of current in the loop.

ABCD is a quadrilateral with right angles at A and C. Points E and F are on the diagonal AC such that DE and BF are both perpendicular to AC.If AE=3cm,DE=5cm and CE=7cm then the length of BF is