Home
Class 7
MATHS
In the given figure, we have AO = BO and...

In the given figure, we have AO = BO and CO = DO. Prove that `DeltaAOC~=DeltaBOD`.

Promotional Banner

Topper's Solved these Questions

  • CONGRUENCE OF TRIANGLES

    MTG IIT JEE FOUNDATION|Exercise Subjective Problems (Short Answer Type)|12 Videos
  • CONGRUENCE OF TRIANGLES

    MTG IIT JEE FOUNDATION|Exercise Subjective Problems (Long Answer Type)|10 Videos
  • CONGRUENCE OF TRIANGLES

    MTG IIT JEE FOUNDATION|Exercise Comprehension Type|6 Videos
  • COMPARING QUANTITIES

    MTG IIT JEE FOUNDATION|Exercise Olympaid/HOTS Corner|20 Videos
  • DATA HANDLING

    MTG IIT JEE FOUNDATION|Exercise Olympiad / Hots Corner |20 Videos

Similar Questions

Explore conceptually related problems

In the given figure, we have PQ = SR and Pr = SQ. Prove that: DeltaPQR~=DeltaSRQ

In the given figure, prove that AC = BD .

In the given figure, we have PQ = SR and Pr = SQ. Prove that: anglePQR=angleSRQ

In the given figure, we have C is the mid-point of AB and DA = DB. Prove that : angleDCA=angleDCB .

In the given figure,AB=AC. prove that :

In the given figure, Oa = OB and OC = OD. Which is the criteria to prove DeltaAOC ~=DeltaBOD .

In the given figure, If AB and CD bisect each other at O, then DeltaAOC is congruent to

In the given figure, ABgtAC. If BO and CO are the bisectors of angleB and angleC respectively then

In the given figure, Delta ABC and Delta DBC have the same base BC. If AD and BC intersect at O, prove that (ar(DeltaABC))/(ar(Delta DBC))=(AO)/(DO)