In the given figure, D and E are the points on the base BC of `DeltaABC` such that `BD=CE, AD= AE` and `angleADE=angleAED`, prove that `DeltaADB cong DeltaAEC`.

In the given figure, D and E are points on the side BC of a DeltaABC such that BD = CE and AD = AE. Show that DeltaABD~=DeltaACE.

In figure ,D and E are Points on side BC of a Delta ABC such that BD=CE and AD=AE.Show that Delta ABD cong Delta ACE.

In the given figure, AB = AC and AD = AE. Prove that: BD = CE

In Figure,AD=AE and D and E are points on BC such that BD=EC .Prove that AB=AC

In the adjoining figure, AD = DC and bisects angleADC . Prove that DeltaADB cong DeltaCDB .

In the given figure, D is a point on side BC of a DeltaABC and E is a point such that CD = DE. Prove that AB+ACgtBE .

A point D is taken on the side BC of a DeltaABC such that BD = 2DC. Prove that ar(DeltaABD) = 2 ar (DeltaADC)

In the given figure, D, E and F are the points where the incircle of the DeltaABC touches F the sides BC, CA and AB respectively. Show that AF+ BD + CE = AE + BF + CD = (perimeter of Delta ABC)

In Figure,AD and BE are respectively altitudes of ABC such that AE=BD .Prove that AD=BE .

D and E are the points on the sides AB and AC respectively of a ABC such that: AD=8cm,quad DB=12cm,quad AE=6cm and CE=9cm. Prove that BC=5/2DE