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Find the value of 1^(3)+2^(3)+......+7^(...

Find the value of `1^(3)+2^(3)+......+7^(3)`

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The correct Answer is:
`(28)^(2)=784`
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MTG IIT JEE FOUNDATION-CUBES AND CUBE ROOTS-Olympiad/HOTS Corner
  1. Find the value of 1^(3)+2^(3)+......+7^(3)

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  2. Simplify : (root6(27)-sqrt(6(3)/4))^(2)

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  3. By what least number 3600 must be multiplied to make it a perfect cube...

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  4. The value of sqrt(0.00001225/(0.00005329))-root3(sqrt0.000064) is

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  5. Evalution : root3(-0.000008/(-0.000216))

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  6. Evalution : root3(0.008)-root3(-512) +root3(2.197)

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  7. (3root3(13824))/(2root3(-15625))+(2root3(-13824))/root3(5832)=

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  8. Cube root of a number when divided by the smallest prime number gives ...

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  9. If a number has digit 2 at unit place, then its cube has digit at its...

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  10. Which of the following in incorrect?

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  11. root(3)(1- 127/343) के बराबर है?

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  12. If root3(x/729)+root3((8x)/729)+root3((27x)/5832)=1 , then find the va...

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  13. (root3(3)+root3(2))(root3(9)+root3(4)-root3(6))=

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  14. (root3(1.728)-root3(0.216))/(root3(2.197)-root3(0.343))=

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  15. If 3^(9)+3^(12)+3^(15)+3^(n) is a perfect cube, n in N,then the value ...

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  16. if x=root3(2(93)/125), then the value of x is

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  17. if sqrtroot3(x xx 0.000009)=0.3 ,then the value of sqrtx is

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  18. root3(1.728)/root3(13.824)xxroot3(4.096)/root3(216)=

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  19. If root3(x/729)+root3((27x)/3375)=1, then find the value of x.

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  20. if x=root3 (13(103)/125), then the value of x is

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  21. Evaluate : root3(4096/64)+3root3(3375/125)

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