Home
Class 8
MATHS
The point (0,5) lies on the...

The point (0,5) lies on the

A

x -axis

B

y-ais

C

both axes

D

none of these

Text Solution

Verified by Experts

Promotional Banner

Topper's Solved these Questions

  • INTRODUCTION TO GRAPHS

    MTG IIT JEE FOUNDATION|Exercise EXERCISE (Multiple Choice Question) (Level-2)|8 Videos
  • INTRODUCTION TO GRAPHS

    MTG IIT JEE FOUNDATION|Exercise EXERCISE (MATCH THE FOLLOWING |2 Videos
  • INTRODUCTION TO GRAPHS

    MTG IIT JEE FOUNDATION|Exercise NCERT SECTIONS (15.3) |4 Videos
  • FOOTSTEPS TOWARDS JEE MAIN

    MTG IIT JEE FOUNDATION|Exercise Section B (Numerical Value Type Questions) |9 Videos
  • LINEAR EQUATIONS IN ONE VARIABLE

    MTG IIT JEE FOUNDATION|Exercise Olympiad/HOTS Corner |15 Videos

Similar Questions

Explore conceptually related problems

The point (0,0) lies on the

Assertion (A) : The point (0,-3) lies on the y-axis. Reason (R ) : The x-coordinate of the point (0,-3) is zero.

If the point (p,q) lies on the line joining the points (-4,5) and (-5,7) , then show that 2p+q+3=0 .

Find the value of c so that the point (3,c) lies on the line represented by 2x-3y+5=0.

Find the value of a so that the point (3,a) lies on the line represented by 2x-3y+5=0

If the point (1,1) lies on the line passing through the points (a,0) and (0,b) then : (1)/(a)+(1)/(b) =

In the xy plane,the segment with end points (3,8) and (-5,2) is the diameter of the circle. The point (k,10) lies on the circle for

If the point (3,k) lies on the line passing through the points (-1,3) and (1,5) then :k=

The gradient of the curve passing through (4,0) is given by (dy)/(dx) - (y)/(x) + (5x)/( (x+2) (x-3))=0 if the point ( 5,a) lies on the curve then the value of a is