The product of two cosecutive positive integers is 201. Represent the above problem in the form of quadratic equation.

Answer

To represent the problem of the product of two consecutive positive integers being equal to 201 in the form of a quadratic equation, we can follow these steps:

### Step-by-Step Solution:

1. **Define the Variables**:
Let the first consecutive positive integer be \( x \). Therefore, the next consecutive integer will be \( x + 1 \).

2. **Set Up the Equation**:
According to the problem, the product of these two integers is equal to 201. We can express this mathematically as:
\[ x \cdot (x + 1) = 201 \]

3. **Expand the Equation**:
Expanding the left side of the equation gives us:
\[ x^2 + x = 201 \]

4. **Rearrange the Equation**:
To form a standard quadratic equation, we need to bring all terms to one side of the equation. We do this by subtracting 201 from both sides:
\[ x^2 + x - 201 = 0 \]

5. **Final Form**:
Now, we have the quadratic equation in the standard form \( ax^2 + bx + c = 0 \), where:
- \( a = 1 \)
- \( b = 1 \)
- \( c = -201 \)

Thus, the required quadratic equation representing the product of two consecutive positive integers being 201 is:
\[ x^2 + x - 201 = 0 \]