Home
Class 10
MATHS
Solve: 6x^(2)+40=31x....

Solve: `6x^(2)+40=31x.`

Promotional Banner

Topper's Solved these Questions

  • QUADRATIC EQUATIONS

    MTG IIT JEE FOUNDATION|Exercise EXERCISE (SUBJECTIVE PROBLEMS) (SHORT ANSWER TYPE)|10 Videos
  • QUADRATIC EQUATIONS

    MTG IIT JEE FOUNDATION|Exercise EXERCISE (SUBJECTIVE PROBLEMS) (LONG ANSWER TYPE)|5 Videos
  • QUADRATIC EQUATIONS

    MTG IIT JEE FOUNDATION|Exercise EXERCISE (COMPREHENSION TYPE )|9 Videos
  • PROBABILITY

    MTG IIT JEE FOUNDATION|Exercise Olympiad/HOTS Corner|26 Videos
  • REAL NUMBERS

    MTG IIT JEE FOUNDATION|Exercise Olympiad/HOTS Corner|15 Videos

Similar Questions

Explore conceptually related problems

Solve 6x^(2)-x-2=0 .

Solve each of the following equatins : 6x^(2)+40=31x

Solve: 8x-4=6x+2

Solve -x^(2)+6x-8 gt0

Solve: 5x-6=4x-2

Write the quotient and remainder when we divide : (6x^(2) - 31 x + 47) by (2x - 5)

Solve for x : 6x^(2) + 11x + 3 = 0

Solve: 6x^(2)-x-2=0 by the factorisation method.

Solve: (6x+7)/(3x+2) = (4x+5)/(2x+3) .

Solve :(6-x)/(x^(2)-4)=2+(x)/(x+2)