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If x^2+p x+q=0a n dx^2+q x+p=0,(p!=q) ha...

If `x^2+p x+q=0a n dx^2+q x+p=0,(p!=q)` have a common roots, show that `p+q=0` . Also, show that their other roots are the roots of the equation `x^2+x+p q=0.`

A

p = q

B

1 + p + q = 0

C

p + q = 0

D

Both (a) and (b)

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If x^(2)+px+q=0andx^(2)+qx+p=0,(p!=q) have a common roots,show that their other 1+p+q=0 .Also,show that their other roots are the roots of the equation x^(2)+x+pq=0.

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Knowledge Check

  • If p, q are the roots of the equation x^(2)+px +q=0 , then

    A
    p = 1, q = -2
    B
    p = 0, q = 1
    C
    p = -2, q = 0
    D
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  • If p and q are the roots of the equation x+ px + q= 0 , then

    A
    `p=1 and q= -2`
    B
    `p= 0 and q= 1`
    C
    `p = -2 and q= 0`
    D
    `p = -2 and q= 1`

  • If p and q are the roots of the equation x^2+px+q=0 , then :

    A
    p = 1 or 0
    B
    p = -2 or 0
    C
    p = -2
    D
    p = 1

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