Home
Class 10
MATHS
In Fig. 6.44, ABC and DBC are two triang...

In Fig. 6.44, ABC and DBC are two triangles on the same base BC. If AD intersects BC at O, show that `(ar (ABC))/( ar (DBC))`= `(AO )/( DO )`

Text Solution

Verified by Experts

The correct Answer is:
`=(AO)/(DO)`
Promotional Banner

Topper's Solved these Questions

  • TRIANGLES

    MTG IIT JEE FOUNDATION|Exercise NCERT Section Exercise 6.5|21 Videos
  • TRIANGLES

    MTG IIT JEE FOUNDATION|Exercise NCERT Section Exercise 6 .6|12 Videos
  • TRIANGLES

    MTG IIT JEE FOUNDATION|Exercise NCERT Section Exercise 6.3|24 Videos
  • SURFACE AREAS AND VOLUMES

    MTG IIT JEE FOUNDATION|Exercise OLYMPIAD/HOTS CORNER|20 Videos

Similar Questions

Explore conceptually related problems

In figure ABC and DBC are two triangles on the same base BC. If AD intersects BC at O, show that (a r(A B C))/(a r(D B C))=(A O)/(D O) .

In the given figure,Delta ABC and Delta DBC are on the same base BC.If AD intersects BC at O , prove that (ar(Delta ABC))/(ar(Delta DBC))=(AO)/(DO)

In the same figure, Delta ABC and Delta DBC are on the same base BC . If AD is intersects BC at O, prove that (ar(Delta ABC))/(ar (Delta DBC))=(AO)/(DO)

In Figure,ABC and DBC are two triangles on the same base BC such that AB=AC and DB=DC .Prove that /_ABD=/_ACD

In the given figure, Delta ABC and Delta DBC have the same base BC. If AD and BC intersect at O, prove that (ar(DeltaABC))/(ar(Delta DBC))=(AO)/(DO)

triangleABC and triangleDBC are two triangles on the same base BC. A and D lies on opposite sides of BC. Prove that (ar(triangleABC))/(ar(triangleDBC))= (AO)/(DO)

ABC and DBC are two isosceles triangles on the same base BC (see Fig. 7.33). Show that /_A B D\ =/_A C D

In figure, ABC and ABD are two triangles on the same base AB. If line segment CD is bisected by AB at O , show that ar (triangleABC)=ar(triangleABD) .

In Figure,ABC and DBC are two isosceles triangles on the same base BC such that AB=AC and DB=CD. Prove that /_ABD=/_ACD

In figure, ABC and BDE are two equilateral triangles such that D is the mid-point of BC. If AE intersects BC at F, show that ar( Delta BDE) = 1/4 ar( Delta ABC)