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Theorem 6.6 : The ratio of the areas of ...

Theorem 6.6 : The ratio of the areas of two similar triangles is equal to the square of the ratio of their corresponding sides.

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The correct Answer is:
`=((AM)/(DN))^(2)`
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Theorem: The ratio of the areas of two triangles is equal to the ratio of the product of their bases and corresponding heights. To prove the above theorem, a. Draw two triangles, and show their bases and heights. b. Write 'given' and 'to prove' from the figures drawn.