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In a DeltaABC , point D is on side AB a...

In a `DeltaABC` , point D is on side AB and point E is on side Ac , such that BCED is a trapezium . If DE : BC = 3 : 5 , then area `(DeltaADE):` area `(DeltaBCED)`=

A

`3 : 4`

B

`9 : 16`

C

`3 : 5`

D

`9 : 25`

Text Solution

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The correct Answer is:
B
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Knowledge Check

  • In DeltaABC , D and E are points on AB and AC respectively such that DE is parallel to BC. If AD= 2 cm, BD = 3 cm, then (ar(DeltaADE))/(ar(DeltaABC)) is

    A
    `4/9`
    B
    `16/81`
    C
    `4/25`
    D
    `2/5`

  • In triangle DeltaABC , points E and F lie on sides AB and AC such that EF||BC . If EF:BC=3:7 then what is the ratio of areas of DeltaAEF and trapezium EBCF ?

    A
    `9:49`
    B
    `9:58`
    C
    `40:49`
    D
    `9:40`

  • D and E are points on sides AB and AC of Delta ABC . DE is parallel to BC. If AD : DB = 2 : 3, what is the ratio of area Delta ADE and area of quadrilateral BDEC ?

    A
    `4:21`
    B
    `4:25`
    C
    `4:29`
    D
    `4:9`

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