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DeltaABCandDeltaCDE are two equilateral ...

`DeltaABCandDeltaCDE` are two equilateral triangles such that D is the mid -point of BC . The ratio of the areas of `DeltaCDEandDeltaABC` is 1 : k then k =

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To solve the problem, we need to find the value of \( k \) in the ratio of the areas of two equilateral triangles \( \Delta ABC \) and \( \Delta CDE \), given that \( D \) is the midpoint of \( BC \). ### Step-by-Step Solution: 1. **Understanding the Triangles**: - We have two equilateral triangles, \( \Delta ABC \) and \( \Delta CDE \). - Point \( D \) is the midpoint of side \( BC \) of triangle \( ABC \). 2. **Identifying Corresponding Sides**: - Since \( D \) is the midpoint of \( BC \), we can denote the length of side \( BC \) as \( a \). Therefore, \( BD = CD = \frac{a}{2} \). 3. **Using the Property of Similar Triangles**: - Since both triangles are equilateral, they are similar. The ratio of the areas of two similar triangles is equal to the square of the ratio of their corresponding sides. 4. **Setting Up the Ratio of Areas**: - The area of triangle \( CDE \) can be expressed in terms of the side \( CD \), which is \( \frac{a}{2} \). - The area of triangle \( ABC \) is based on the side \( a \). 5. **Calculating the Areas**: - The area of triangle \( ABC \) is given by the formula: \[ \text{Area}_{ABC} = \frac{\sqrt{3}}{4} a^2 \] - The area of triangle \( CDE \) is given by: \[ \text{Area}_{CDE} = \frac{\sqrt{3}}{4} \left(\frac{a}{2}\right)^2 = \frac{\sqrt{3}}{4} \cdot \frac{a^2}{4} = \frac{\sqrt{3}}{16} a^2 \] 6. **Finding the Ratio of Areas**: - Now, we can find the ratio of the areas: \[ \frac{\text{Area}_{CDE}}{\text{Area}_{ABC}} = \frac{\frac{\sqrt{3}}{16} a^2}{\frac{\sqrt{3}}{4} a^2} = \frac{\frac{1}{16}}{\frac{1}{4}} = \frac{1}{4} \] 7. **Expressing in Terms of k**: - We are given that the ratio of the areas of \( \Delta CDE \) to \( \Delta ABC \) is \( 1 : k \). - From our calculation, we found that: \[ \frac{\text{Area}_{CDE}}{\text{Area}_{ABC}} = \frac{1}{4} \] - Therefore, we can write: \[ 1 : k = 1 : 4 \] - This implies that \( k = 4 \). ### Final Answer: Thus, the value of \( k \) is \( 4 \).
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Knowledge Check

  • DeltaPQR and DeltaQST are two equilateral triangles such that T is the mid-point of QR. Find the ratio of the areas of DeltaPQR and DeltaQST .

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