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The radius of the base of a right circul...

The radius of the base of a right circular cone is r. It is cut by a plane parallel to the base at a height h from the base. The distance of the boundary of the surface from the centre of the base of the frustum is `sqrt(h^(2) + (r^(2))/9)`. Show that the volume of the frustum is 13/27`pir^(2)h`.

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The correct Answer is:
`13/27pir^2h`
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