The relative density of silver is 10.8 If the density of water be `1.0xx10^(3) kg m^(-3)` caluclate the density of silver isn SI units.

Explanation

We know that,
Relative density of a substance `=("Density of the substance")/("Density of water")`
Here , Relative density of silver `=10.8`
Density of silver `=?`
And, Density of water `=1.0xx10^(3)kgm^(-3)`
Now, putting these values of relative density of silver and density of water in the above formula, we get
`10.8=("Density of silver")/(1.0xx10^(3))`
So, density of silver `=10.8xx1.0xx10^(3)kgm^(-3)`
`=10.8xx10^(3)kgm^(-3)`