A truck is of mass `50,000` kg. Its tyres exert a pressure of `2,500,000` Pa. The surface area of tyres in contact with ground is ( Take `g=10"m s"^(-2)` )

Options

A. `2"m"^(2)`
B. `0.2"m"^(2)`
C. `2.5"m"^(2)`
D. `2.75"m"^(2)`

Answer

B

Explanation

Force = `50,000"kg"xx10 "m s"^(-2)=500,000 N`,
Given, `P=2,500,000` Pa
`:. Area=("Force")/("Pressure")=(500,000)/(2,500,000)=0.2m^(2)`