A source is producing 1500 sound waves in 3 seconds. If the distance covered by a compression and an adjacent rarefaction be 68 cm, find: (a) frequency, (b) wavelength, and (c) velocity, of the sound wave.

Explanation

The formula for calculating the velocity of a sound wave is :
`v = upsilon xx lambda`
Here, Frequency, `v = 500` Hz
Wavelength, `lambda = 68` cm
`= (68)/(100) m =0.68` m
Putting these values of ` upsilon and lambda` in the given formula, we get,
`v = 500 xx 0.68 = 340"m s"^(-1)`
Thus, the velocity (or speed) of the sound wave is `340"m s"^(-1)`.