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A light pointer fixed to one prong of a tuning fork touches gnetly a smoked vertical plate. The fork is set vibrating and the plate is allowed to fall freely. 8 complete oscilllations are counted when the plate falls through 10cm.What is the frequency of the tuning fork?

A

360 Hz

B

280 Hz

C

560 Hz

D

56 Hz

Text Solution

Verified by Experts

The correct Answer is:
D
Time of fall `= sqrt((2h)/( g) ) = sqrt((2 xx 10)/( 1000) ) = sqrt((1)/(50))`
In this time number of oscillations are eight
So time for 1 oscillation `= (1)/( 8 sqrt50)`
Frequency `= 8 sqrt(50) Hz = 56 Hz`
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