If man were standing unsymmetrically between parallel cliffs, claps his hands and starts hearing a series of echoes at intervals of 1 s. If speed of sound in air is `340"m s"^(-1)`, the distance between two cliffs would be

Options

A. 340 m
B. 510 m
C. 170 m
D. 680 m

Answer

B

Explanation

Let x be distance of person from one cliff and y be distance of person from 2nd cliff. Let `y gt x`.
`therefore x + x = v xx t_1 = 340 xx 1 = 340`
`x = 170` m
`y + y = v xx t_2 = 340 xx 2 = 680`
`y = 340` m.
Distance between two cliffs`= x + y = 170 + 340 = 510` m