Home
Class 9
PHYSICS
When a siren of a fire engine approaches...

When a siren of a fire engine approaches an observer at a speed of `10"m s"^(-1)`, taking the velocity of sound is `340"m s"^(-1)`, if the frequency of the siren is 600 Hz, the frequency heard by the observer is

A

580 Hz

B

620 Hz

C

600 Hz

D

none of these

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem of finding the frequency heard by an observer when a siren approaches, we can use the Doppler effect formula for sound. Here’s a step-by-step breakdown of the solution: ### Step 1: Identify the given values - Speed of sound (V) = 340 m/s - Speed of the source (Vs) = 10 m/s (since the fire engine is approaching, this is positive) - Frequency of the siren (Fs) = 600 Hz ### Step 2: Understand the formula for the Doppler effect The formula to calculate the frequency heard by the observer (Fl) when the source is moving towards the observer is given by: \[ Fl = \frac{V + Vl}{V - Vs} \times Fs \] Where: - Fl = frequency heard by the listener - V = speed of sound - Vl = speed of the listener (0 m/s, since the observer is at rest) - Vs = speed of the source ### Step 3: Substitute the values into the formula Since the listener is at rest, Vl = 0. Therefore, the formula simplifies to: \[ Fl = \frac{V}{V - Vs} \times Fs \] Substituting the known values: \[ Fl = \frac{340}{340 - 10} \times 600 \] ### Step 4: Calculate the denominator Calculate \(340 - 10\): \[ 340 - 10 = 330 \] ### Step 5: Substitute back into the equation Now substitute back into the equation: \[ Fl = \frac{340}{330} \times 600 \] ### Step 6: Calculate the fraction Now calculate the fraction: \[ \frac{340}{330} = \frac{34}{33} \] ### Step 7: Multiply by the frequency of the siren Now multiply by the frequency of the siren: \[ Fl = \frac{34}{33} \times 600 \] ### Step 8: Perform the multiplication Calculate \( \frac{34 \times 600}{33} \): \[ Fl = \frac{20400}{33} \approx 618.18 \text{ Hz} \] ### Step 9: Round to the nearest option The frequency heard by the observer is approximately 618.18 Hz, which can be rounded to 620 Hz. ### Final Answer The frequency heard by the observer is approximately **620 Hz**. ---

To solve the problem of finding the frequency heard by an observer when a siren approaches, we can use the Doppler effect formula for sound. Here’s a step-by-step breakdown of the solution: ### Step 1: Identify the given values - Speed of sound (V) = 340 m/s - Speed of the source (Vs) = 10 m/s (since the fire engine is approaching, this is positive) - Frequency of the siren (Fs) = 600 Hz ### Step 2: Understand the formula for the Doppler effect ...
Promotional Banner

Topper's Solved these Questions

  • SOUND

    MTG IIT JEE FOUNDATION|Exercise Exercise (Match the Following)|4 Videos
  • SOUND

    MTG IIT JEE FOUNDATION|Exercise Exercise (Assertion & Reason Type)|10 Videos
  • SOUND

    MTG IIT JEE FOUNDATION|Exercise Exercise (Multiple Choice Questions) LEVEL - 1|30 Videos
  • MOTION

    MTG IIT JEE FOUNDATION|Exercise Olympiad/HOTS Corner|21 Videos
  • THRUST AND PRESSURE

    MTG IIT JEE FOUNDATION|Exercise Olympiad/HOTS Corner|15 Videos

Similar Questions

Explore conceptually related problems

A whistle emitting a sound of frequency 450 Hz approaches a stationary observer at a speed of 33 m/s. Velocity of sound is 330 m/s. The frequency heard by the observer, in Hz, is :

A source of sound is moving away from an observer at rest with a velocity of 50 m s^(-1) . If the frequency of sound is 200 Hz , find the apparent frequency observed by the observer. (Take velocity of sound = 300 m s^(-1))

A source of sound and a listener are moving towards each other . The velocity of the source is 20 m s^(-1) and that of the observer is 15 m s^(-1) . If the velocity of sound is 340 m s^(-1) and its frequency is 640 Hz, find the apparent frequency of the sound .

A train approaching a railway platform with a speed of 20 m s^(-1) starts blowing the whistle. Speed of sound in air is 340 m s^(-1) . If the frequency of the emitted sound from the whistle is 640 Hz, the frequency of sound as heard by person standing on the platform

At t=0 , observer and source are at same place. Now the source is projected with velocity 60 sqrt2 m/s at 45 ^(@) . Natural frequency of source is 1000 Hz.find the frequency heard by the observer at t=2s. Take speed of sound = 340 m/s

An engine of a train is moving towards a platform with a velocity of 100 m s^(-1) . If the frequency of sound produced is 200 Hz , find the apparent frequency of the sound as observed by an observer standing on the platform (Taking velocity of sound = 320 m s^(-1) ) .

A source of sound of frequency 500 Hz is moving towards an observer with velocity 30 m/s . The speed of sound is 330 m/s . the frequency heard by the observer will be

The driver of a car travelling with a speed of 30 m/s towards a wall sounds a siren of frequency 500 Hz. If the velocity of sound in air is 330 m/s, then the frequency of the sound reflected from the wall and as heard by the driver is

When an engine passes near to a stationary observer then its apparent frequencies occurs in the ratio 5/3. if the velocity of sound is 340 m/s then speed of engine is

MTG IIT JEE FOUNDATION-SOUND-Exercise (Multiple Choice Questions) LEVEL - 2
  1. A bat emits ultrasonic sound of frequency 100 kHz in air. If this soun...

    Text Solution

    |

  2. During night, distant sounds such as that of traffic and loudspeakers ...

    Text Solution

    |

  3. A longitudal wave is produced on a slinky. The wave travels at a speed...

    Text Solution

    |

  4. Sound travels at a speed of 334"m s"^(-1) in air. This means that

    Text Solution

    |

  5. Non-mechanical wave can travel

    Text Solution

    |

  6. In case of a travelling wave, the reflection at a rigid boundary will ...

    Text Solution

    |

  7. When sound is produced in an aeroplane with a velocity of 200 m/s hori...

    Text Solution

    |

  8. A tuning fork of frequency 250 Hz produces a beat frequency of 10 Hz w...

    Text Solution

    |

  9. If man were standing unsymmetrically between parallel cliffs, claps hi...

    Text Solution

    |

  10. A man is watching two trains, one leaving and the other coming in with...

    Text Solution

    |

  11. When two waves of almost equal frequencies v(1) and v(2) reach at a po...

    Text Solution

    |

  12. Blowing a horn of 500 Hz frequency, a car A is moving in the opposite ...

    Text Solution

    |

  13. When a siren of a fire engine approaches an observer at a speed of 10"...

    Text Solution

    |

  14. A bus is moving with a velocity of 5 ms^(-1) towards a huge wall. The ...

    Text Solution

    |

  15. A source of sound produces wave of 60 cm wavelength. This source is mo...

    Text Solution

    |

  16. A source of sound is rotating in the anticlockwise direction on a circ...

    Text Solution

    |

  17. Two tuning forks, A and B, produce notes of frequencies 258 Hz and 262...

    Text Solution

    |

  18. A train whistling at constant frequency is moving towards a station at...

    Text Solution

    |

  19. Earthquakes generate sound waves inside the earth. Unlike a gas, the e...

    Text Solution

    |

  20. A SONAR system fixed in a submarine operates at a frequency 40.0kHz. A...

    Text Solution

    |