A mountaineer of weight 300 N climbs up a rock face of vertical height 600 m in 5400 s. What is the average power she generates against gravity during this time?

Options

A. 20 W
B. 33 W
C. 18 W
D. 72 W

Answer

B

Explanation

Total work done by climber = weight ` xx` height
` W = ( 300 xx 600) J = 1 . 8 xx 10^(5) J`
Total time taken by climber , T = 5400 s
Average power , `P_(av) = (W)/( t) = (1 . 8 xx 10^(5) J)/( 5400 s) = 35 W `