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The distance between two bodies becomes ...

The distance between two bodies becomes 6 times more than the usual distance. Then the F becomes

A

36 times

B

6 times

C

12 times

D

` (1)/( 36)` times

Text Solution

Verified by Experts

The correct Answer is:
D

As, force ` F prop (1)/(r^(2))` , so when distance becomes
6 times more than initial then, becomes , `F. prop (F)/((6)^(2)) = (F)/(36)`
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