A mass of 100 g strikes the wall with speed `5 m//s` at an angle as shown in figure and it rebounds with the same speed it the contact time is `2 xx 10^(-3) sec`. What is the force applied on the mass by the wall :

Options

A. `250 sqrt(3)` to right
B. 250 N to right
C. `250 sqrt(3)` N to left
D. 250 N to left

Answer

C

Explanation

Change of momentum taking place in a short time
`= - mv sin theta - ( + mv sin theta) = - 2 m v sin theta `
`= - 2 xx 0.100 xx 5 (sqrt(3))/(2) = - 0 . 500 sqrt(3)`
The force applied = rate of change of momentum
`= - ( 0 . 500 xx sqrt(3))/( ( 2 xx 10^(-3) s)) = 250 sqrt(3)` N to the left