A rock climber of weight 600 N climbs up a rock face of vertical height 300 m in 3600 s. What is the average power he generates against gravity during this time ?

Options

A. 0.020 w
B. 50 W
C. 1800 W
D. 7200 w

Explanation

To find the average power generated by the rock climber against gravity, we can follow these steps:

### Step 1: Identify the Given Data
- Weight of the climber (W) = 600 N
- Height climbed (H) = 300 m
- Time taken (T) = 3600 s

### Step 2: Understand the Concept of Work Done
The work done against gravity when climbing is equal to the increase in gravitational potential energy. This can be calculated using the formula:
\[ \text{Work Done} = \text{Weight} \times \text{Height} \]
Thus, the work done (W_d) by the climber is:
\[ W_d = W \times H \]

### Step 3: Calculate the Work Done
Substituting the values:
\[ W_d = 600 \, \text{N} \times 300 \, \text{m} \]
\[ W_d = 180000 \, \text{J} \] (Joules)

### Step 4: Calculate the Average Power
Power (P) is defined as the work done per unit time. The formula for average power is:
\[ P = \frac{\text{Work Done}}{\text{Time Taken}} \]
Substituting the values:
\[ P = \frac{180000 \, \text{J}}{3600 \, \text{s}} \]

### Step 5: Perform the Calculation
Calculating the power:
\[ P = \frac{180000}{3600} \]
\[ P = 50 \, \text{W} \]

### Final Answer
The average power generated by the climber against gravity is:
\[ P = 50 \, \text{W} \]

---