An object is weighed in the following places using a spring balance. In which place will it weigh the heaviest?

Options

A. on the moon
B. at the equator
C. at the pole
D. at the centre of earth

Explanation

To determine where an object will weigh the heaviest among the four given locations (on the Moon, at the equator of the Earth, at the pole, and at the center of the Earth), we need to analyze the acceleration due to gravity (g) at each of these locations. The weight of an object is given by the formula:

\[ \text{Weight} = m \cdot g \]

where:
- \( m \) is the mass of the object (which remains constant),
- \( g \) is the acceleration due to gravity at that location.

### Step-by-Step Solution:

1. **Identify the locations and their characteristics**:
- **On the Moon**: The acceleration due to gravity is approximately \( 1.6 \, \text{m/s}^2 \).
- **At the Equator of the Earth**: The acceleration due to gravity is approximately \( 9.8 \, \text{m/s}^2 \).
- **At the Pole of the Earth**: The acceleration due to gravity is slightly more than at the equator due to the Earth being an oblate spheroid (flattened at the poles). It is approximately \( 9.83 \, \text{m/s}^2 \).
- **At the Center of the Earth**: The acceleration due to gravity is \( 0 \, \text{m/s}^2 \) because there is no mass at the center to exert gravitational force.

2. **Compare the values of g**:
- Moon: \( g \approx 1.6 \, \text{m/s}^2 \)
- Equator: \( g \approx 9.8 \, \text{m/s}^2 \)
- Pole: \( g \approx 9.83 \, \text{m/s}^2 \)
- Center of the Earth: \( g = 0 \, \text{m/s}^2 \)

3. **Determine the maximum value of g**:
- Among the values calculated, the highest value of g is at the pole, which is approximately \( 9.83 \, \text{m/s}^2 \).

4. **Conclusion**:
- Since weight is directly proportional to g, the object will weigh the heaviest at the pole, where the acceleration due to gravity is the greatest.

### Final Answer:
The object will weigh the heaviest at the **pole**.

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