Home
Class 8
PHYSICS
PASSAGE-I: Ramu applied a force of 10 N ...

PASSAGE-I: Ramu applied a force of 10 N on a body to move it from rest. He wants to express the applied force in terms of various system of units.
Express 10N force in terms of `g cm s^(-2)`

A

`10^(5) g cm s^(-2)`

B

`10^(6) g cm s^(-2)`

C

`10^(3) g cm s^(-2)`

D

`10^(4)g cm s^(-2)`

Text Solution

Verified by Experts

The correct Answer is:
B

`1 N = 10^(5) g cm s^(-2)`
`10 N = 10^(6) g cm s^(-2)`
Promotional Banner

Topper's Solved these Questions

  • FORCE AND PRESSURE

    MTG IIT JEE FOUNDATION|Exercise EXERCISE (SUBJECTIVE PROBLEMS VERY SHORT ANSWER TYPE) |15 Videos
  • FORCE AND PRESSURE

    MTG IIT JEE FOUNDATION|Exercise EXERCISE (SUBJECTIVE PROBLEMS SHORT ANSWER TYPE) |10 Videos
  • FORCE AND PRESSURE

    MTG IIT JEE FOUNDATION|Exercise EXERCISE (Assertion & Reason Type)|10 Videos
  • FOOTSTEPS TOWARDS NEET

    MTG IIT JEE FOUNDATION|Exercise MCQ|45 Videos
  • FRICTION

    MTG IIT JEE FOUNDATION|Exercise OLYMPIAD/HOTS CORNER|15 Videos

Similar Questions

Explore conceptually related problems

PASSAGE-I: Ramu applied a force of 10 N on a body to move it from rest. He wants to express the applied force in terms of various system of units. Express 10 N force in terms of kgf

PASSAGE-I: Ramu applied a force of 10 N on a body to move it from rest. He wants to express the applied force in terms of various system of units. Express 10 N force in terms of dynes:

To produce a couple of 20 N m on a disc of radius 10 cm, what is the force to be applied.

If a force of 50 N is applied on a body and it is still at rest, then find the magnitude of static frictional force acting on it.

A gardener pushes a lawn roller on a rough surface. He applies a force of 150 N over a distance of 5 m. After he gets tired and his applied force reduces linerly with distance to 75 N. The total distance moved is 10 m. Plot the force applied by the gardencer and the frictional force, which is 75 N versus displacement. Calculate the work done by t he two forces over 10 m.

A force of 8 N is applied to a body at a distance of 20 cm from the point at which it is pivoted. Calculate the torque or moment of force about the pivot.

A body of mass 2 kg initially at rest moves under the action of an applied horizontal force of 7N on a table with coefficient of kinetic friction =0.1 . Calculate the (a) work done by applied force in 10s. (b) work done by friction in 10s. (c ) work done by the net force on the body in 10s. (d) change in K.E. of body in 10s, and interpret your result.

A block of mass 2 kg initially at rest moves under the action of an applied horizontal force of 6 N on a rough horizontal surface. The coefficient of friction between block and surface is 0.1. The work done by the applied force in 10 s is (Take g = 10 ms^(-2) )