A piece of wood is floating in water kept in a bottle. The bottle is connected to an air pump. Neglect the compressibility of water. When more air is pushed into the bottle from the pump, the piece of wood will float with:

Options

A. larger part in the water
B. lesser part in the water
C. same part in the water
D. will sink to the bottom

Explanation

To solve the question, we need to analyze the situation of the piece of wood floating in water when air is pumped into the bottle. Here’s a step-by-step breakdown:

### Step 1: Understand the Initial Condition
- We have a piece of wood floating in water. The wood displaces a certain volume of water, which creates an upward buoyant force equal to the weight of the water displaced.

**Hint:** Remember that an object floats when the buoyant force equals its weight.

### Step 2: Consider the Effect of Air Pressure
- The bottle is connected to an air pump, which means we can increase the air pressure inside the bottle by pumping in more air. However, we are told to neglect the compressibility of water.

**Hint:** Think about how increasing air pressure affects the forces acting on the wood.

### Step 3: Analyze the Forces on the Wood
- When more air is pumped into the bottle, the air pressure increases. However, the weight of the wood and the density of the water remain unchanged (since we are neglecting the compressibility of water).

**Hint:** The buoyant force depends on the volume of water displaced, which is related to the weight of the wood.

### Step 4: Determine the Effect on the Wood’s Floating Condition
- Since the weight of the wood does not change and the density of the water does not change, the amount of water displaced by the wood remains the same. Therefore, the piece of wood will continue to float at the same level in the water.

**Hint:** Consider what happens to the equilibrium condition of the wood as air pressure increases.

### Step 5: Conclusion
- The piece of wood will float with the same part in the water as before, regardless of the increased air pressure in the bottle.

**Final Answer:** The piece of wood will float with the same part in the water (Option 3).

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