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A train starting from rest moves with a ...

A train starting from rest moves with a uniform acceleration of `0.2 m//s^(2)` for 5 minutes . Calculate the speed acquired and the distance travelled in this time.

Text Solution

Verified by Experts

Acceleration `a=0.2 m//s^(2)` , initial velocity u=0 Time t=5 minutes = 300 s
Final velocity,v =?
`a=(v-u)/(t) rarr 0.2 (v)/(300) rarr v=60 m//s`
Average velocity
`v_(av)=(v+u)/(2)=(60+0)/(2)=30 m//s`
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