`{:("List-I","List-II"),("(P)Scalar quantity",(1) "force"),("(Q)Vector quantity",(2) m s^(-2)),("(R )Acceleration",(3) m s^(-1)),("(S) Velocity",4 "time"):}`

Options

A. P-4, Q-1, R-2, S-3
B. P-2, Q-3, R-1, 5-4
C. P-1, Q-4, R-3, 5-2
D. P-3, Q-2, R-4, S-1

Answer

To solve the problem, we need to match the items from List-I with the correct items from List-II based on their definitions and units.

### Step-by-Step Solution:

1. **Identify Scalar Quantity (P)**:
- A scalar quantity is defined as a quantity that has only magnitude and no direction.
- The only option in List-II that corresponds to a scalar quantity is **time**.
- Therefore, we match **(P) Scalar quantity** with **(4) time**.

2. **Identify Vector Quantity (Q)**:
- A vector quantity is defined as a quantity that has both magnitude and direction.
- The option in List-II that corresponds to a vector quantity is **force**.
- Therefore, we match **(Q) Vector quantity** with **(1) force**.

3. **Identify Acceleration (R)**:
- Acceleration is defined as the rate of change of velocity per unit time.
- Its SI unit is **meter per second squared (m/s²)**.
- Therefore, we match **(R) Acceleration** with **(2) m s^(-2)**.

4. **Identify Velocity (S)**:
- Velocity is defined as the distance traveled per unit time.
- Its SI unit is **meter per second (m/s)**.
- Therefore, we match **(S) Velocity** with **(3) m s^(-1)**.

### Final Matches:
- (P) Scalar quantity → (4) time
- (Q) Vector quantity → (1) force
- (R) Acceleration → (2) m s^(-2)
- (S) Velocity → (3) m s^(-1)

### Conclusion:
The correct matching is:
- (P) → (4)
- (Q) → (1)
- (R) → (2)
- (S) → (3)

Thus, the answer is option 1.