`{:("List-I","List-II"),("(P)1 parsec",(1) 9.46728xx10^(15) m ),("(Q)1 light year",(2) 3.084 xx10^(16) m),("(R )Electric current",(3) "kelvin"),("(S) Temperature",(4) "ampere"):}`

Options

A. P-1, Q-2, R-3, S-4
B. P-3, Q-4, R-2, 5-1
C. P-2, Q-1, R-4, 5-3
D. P-4, Q-3, R-1, S-2

Answer

To solve the matching question between List-I and List-II, we will analyze each item in List-I and find its corresponding item in List-II based on the definitions and values provided.

### Step-by-Step Solution:

1. **Identify the first item (P): 1 parsec**
- A parsec is a unit of distance used in astronomy. It is defined as the distance at which one astronomical unit subtends an angle of one arcsecond.
- It is known that 1 parsec is approximately equal to 3.26 light years.
- We also know that 1 light year is equal to \(9.46728 \times 10^{15}\) meters.
- Therefore, we can calculate:
\[ 1 \text{ parsec} = 3.26 \text{ light years} = 3.26 \times 9.46728 \times 10^{15} \text{ m} \approx 3.084 \times 10^{16} \text{ m} \]
- Thus, **(P) 1 parsec matches with (2) \(3.084 \times 10^{16} \text{ m}\)**.

2. **Identify the second item (Q): 1 light year**
- As mentioned, 1 light year is defined as the distance that light travels in one year.
- It is given that:
\[ 1 \text{ light year} = 9.46728 \times 10^{15} \text{ m} \]
- Therefore, **(Q) 1 light year matches with (1) \(9.46728 \times 10^{15} \text{ m}\)**.

3. **Identify the third item (R): Electric current**
- The unit of electric current is defined as the ampere.
- Therefore, **(R) Electric current matches with (4) ampere**.

4. **Identify the fourth item (S): Temperature**
- The unit of temperature in the International System of Units (SI) is the kelvin.
- Therefore, **(S) Temperature matches with (3) kelvin**.

### Final Matching:
- (P) 1 parsec → (2) \(3.084 \times 10^{16} \text{ m}\)
- (Q) 1 light year → (1) \(9.46728 \times 10^{15} \text{ m}\)
- (R) Electric current → (4) ampere
- (S) Temperature → (3) kelvin

### Conclusion:
The final answer is:
- P → 2
- Q → 1
- R → 4
- S → 3