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The time period of a satellite of earth ...

The time period of a satellite of earth is 5 hours. If the separation between the centre of earth and the satellite is increased to 4 times the previous value, the new time period will become-

Text Solution

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According to Kepler.s third law, Top T^2 prop r^3`
` T_2/T_1 = (r_2/r_1)^(3//2) = ((4r)/(r ))^(3//2) = 8`
or `T_2 = 8T_1 = 8xx 5` hours = 40 hours
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