`FeS_(2) + O_(2) rarr Fe_(2) O_(3) + SO_(2)`
Balanced Equation

FeS_(2) is converted into Fe_(2)O_(3) according to the following equation 4FeS_(2) +xO_(2) to 2Fe_(2)O_(3) + ySO_(2) x and y used in the equation have the values .

Equivalent weight of FeS_(2) in the half reaction FeS rarr Fe_(2)O_(3) + SO_(2) is :

2Fe+(3)/(2)O_(2)rarr Fe_(2)O_(3)" "xkJ//mol e 2Fe+O_(2) rarr 2FeO" " ykJ //mol e The DeltaH to form one mole of Fe_(3)O_(4) from Fe and O_(2) is :