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Why Cd^(2+) salts are white ? Cd=48...

Why `Cd^(2+)` salts are white ? Cd=48

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The electronic configuiration of `Cd (Z = 48)` is `[Kr]^(36) 5s^2 4d^10`
`Cd^(2+) : [Kr]^(36) 4d^(10)`

Since `Cd^(2+)` has fully filled d-subshell therefore `Ca^(2+)` salts are white.
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