Write the formula of sulphur dioxide . Also name the elements presents in them.

Explanation

`Fe(Z = 26) : [Ar]^18 3d^6 4s^2`
`Fe^(2+) : [Ar]^(18) 3d^6 " (4 unpaired electron)"`
`Fe^(3+) : [Ar]^(18) 3d^5 " (5 unpaired electrons)"`.

As `Fe^(3+)` has more unpaired electron than `Fe^(2+), Fe^(3+)` is more Paramagnetic or has high moment the `Fe^(2+)`
Magnetic moment `mu_S = sqrt(n(n + 2)) B.M.`
Magnetic moment of `Fe^(2+)` ion = `mu_S = sqrt(4(4+ 2)) = sqrt(24) = 4.9. B.M. `
Magnetic moment of `Fe^(3+)` ion = `mu_S = sqrt(5(5 + 2)) = sqrt(35) = 5.9 B.M`.