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The projection of veca=2hati+3hatj+2hatk...

The projection of `veca=2hati+3hatj+2hatk` on `vecb=hati+2hatj+hatk` is equal to:

A

`(sqrt(6))/14`

B

`(5sqrt(6))/3`

C

`5/(sqrt(6))`

D

`6/(sqrt(14))`

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The correct Answer is:
b
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Find the scalar projection of : veca=2hati+3hatj+2hatk on vecb=hati+2hatj+hatk .

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ACCURATE PUBLICATION-VECTOR ALGEBRA-QUESTIONS CARRYING 2 MARKS
  1. The projection of veca=2hati+3hatj+2hatk on vecb=hati+2hatj+hatk is eq...

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  2. Prove that the figure formed by joining the mid-points of the pairs of...

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  3. If veca=hati+hatj+hatk,vecb=2hati-hatj+3hatk,vecc=hati-2hatj+hatk, the...

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  4. If veca=2hati-hatj+3hatk,vecb =hati+hatj-hatk, vecc=3hati+4hatj-5hatk,...

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  5. If veca=5hati+hatj-4hatk, vecb=2hati-3hatj+hatk and vecc=hati+3hatj-2h...

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  6. Show that the points A(1,2,7), B(2,6,3) and C(3,10,-1) are collinear.

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  7. Show that the three points with position vectors 2hati+6hatj+3hatk,hat...

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  8. Show that the points : A(-2hati+3hatj+5hatk), B(hati+2hatj+3hatk) and ...

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  9. Show that . the points (2. 6, 3), (1, 2, 7) and (3, 10, -1) are collin...

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  10. Find the position vector of a point R which divides the line joining t...

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  11. Find the position vector of a point R which divides the line joining t...

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  12. Find the angle between two vectors veca and vecb with magnitudes sqrt3...

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  13. For any two vectors veca and vecb, prove that |veca.vecb|le|veca||vec...

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  14. For any two vectors veca and vecb, prove that : |veca+vecb|le|veca|+|v...

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  15. If |veca|=3, |vecb|=4 and |vecc|=5 and each of them is perpendicular ...

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  16. If |veca|=2, |vecb|=3 and |vecc|=4 and each of them is perpendiculart...

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  17. If |veca|=7, |vecb|=1 and |vecc|=5 and each of them is perpendicular ...

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  18. Let veca,vecb,vecc be the three vectors of magnitude 5, 3, I respectiv...

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  19. Find the scalar projection of : veca=2hati-hatj-3hatk on vecb=3hati-5h...

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  20. Find the scalar projection of : veca=7hati+3hatj+6hatk on vecb=5hati-2...

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  21. Find the scalar projection of vecb on veca where : veca=2hati-2hatj+ha...

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