If `veca` and `vecb` are adjacent sides of a rhombus, then`veca.vecb=0`

If veca" and "vecb are any two vectors, then (veca xx vecb)^(2)= |veca|^(2)|vecb|^(2)-(veca* vecb)^(2) .

If veca and vecb are two vectors , then prove that (vecaxxvecb)^(2)=|{:(veca.veca" ",veca.vecb),(vecb.veca" ",vecb.vecb):}|

If veca and vecb are vectors such that |veca|=2,|vecb|=3 and veca*vecb=4 , then |veca-vecb| is equal to :

If vectors veca and vecb are non collinear then veca/(|veca|)+vecb/(|vecb|) is (A) a unit vector (B) in the plane of veca and vecb (C) equally inclined to veca and vecb (D) perpendicular to veca xx vecb

Solve: vecrxxvecb=veca, where veca and vecb are given vectors such that veca.vecb=0 .

If veca and vecb are two vectors such that |\veca.vecb|=|\vecaxxvecb| , then what is the angle between veca and vecb ?

If veca,vecb and vecc are three unit vectors such that veca*vecb=veca*vecc=0 and angle between vecb and vecc is pi/6 , prove that veca=+-2(vecb xxvecc) .