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An urn contains 4 red and 7 blue balls ....

An urn contains `4` red and `7` blue balls . Two balls are drawn at random with replacement . Find the probability of getting
(i) `2` red balls
(ii) `2` blue balls
(iii) one red and one blue ball.

Text Solution

Verified by Experts

The correct Answer is:
(i) `(49)/(121) (ii) (16)/(121) (iii) (56)/(121)`
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