Home
Class 12
MATHS
The equation of the tangent to the curve...

The equation of the tangent to the curve `y=x^(4)-6x^(3)+13x^(2)-10x+5` at the point `x=1` is . . . . . .

Text Solution

Verified by Experts

The correct Answer is:
`2x-y+1=0`
Promotional Banner

Topper's Solved these Questions

  • SAMPLE QUESTION PAPER-X (UNSOLVED)

    ACCURATE PUBLICATION|Exercise SECTION-C|8 Videos

  • SAMPLE QUESTION PAPER-X (UNSOLVED)

    ACCURATE PUBLICATION|Exercise SECTION-D|6 Videos

  • SAMPLE QUESTION PAPER-X (UNSOLVED)

    ACCURATE PUBLICATION|Exercise SECTION-A (TRUE OR FALSE)|8 Videos

  • SAMPLE QUESTION PAPER-VIII

    ACCURATE PUBLICATION|Exercise SECTION-D|6 Videos

  • SAMPLE QUESTIONS PAPER - III (UNSOLVED)

    ACCURATE PUBLICATION|Exercise SECTION - D|6 Videos

Similar Questions

Explore conceptually related problems

Find the equations of the tangent line to the curve: y=x^3 - 3x +5 at the point (2,7)

Find the equation of the tangent to the curve y=3x^2 at (1,1)

Find the equations of the tangent line to the curve: y = 2x^2 + 3y^2 = 5 at the point (1,1)

Find the equation of the tangent to the curve y = -5x^2 + 6x + 7 at the point (1/2 , 35/4)

The slope of the tangent to the curve (y-x^5)^2=x(1+x^2)^2 at the point (1,3) is.

Find the length of the tangent for the curve y=x^3+3x^2+4x-1 at point x=0.

The equation of the tangents to the curve (1+x^(2))y=1 at the points of its intersection with the curve (x+1)y=1 , is given by