A wire of length 2.0 m , diameter 1.0 mm has `50xx10^(-3)Omega` resistance . Calculate the resistivity of the material of the wire .

Explanation

Length of wire `=l=2.0m`
Diametr of the wire =1.0 mm
Radius of the wire `=r=(1)/(2)`
0.6 m
`r=0.5xx10^(3)`m
`r=5xx10^(-4)`m
Resistance of the wire `=R=50xx10^(-3)Omega`
Resistivity of the maerial of wire `=l=` ? `rho=(RA)/(L)`
`rho=(R(IIr^(2)))/(L)`
`rho=(50xx10^(-3))/(2)xx(22)/(7)xx(5xx10^(-4))^(2)`
`rho=(""^(2)cancel50xx10^(-3))/(2)xx(22)/(7)xx25xx10^(-8)`
`rho=(25xx22xx25xx25xx10^(-8-3))/(7)`
`rho=1964.2xx10^(-11)Omegam`
`rho=1.96xx10^(-8)Omegam`