A cell of emf 1.4 volt gives a balance point at 70 Cm length of a potentiometer wire, for another cell , the balance point shifts to 60 Cm .find the emf of the second cell .

Explanation

`E_(1)=1.4` Volt
`l_(1)=7.0Cm`
`E_(2)=?`
`l_(2)=60`Cm
`(E_(1))/(E_(2))=(l_(1))/(l_(2))`
`(1.4)/(E_(2))=(70)/(60)rArrE_(2)=(1.4xx60)/(70)``E_(2)=(overset(3)cancel60)/(cancel70_(10))xx(cancel14^(2))/(cancel10_(5))`
`E_(2)=(6)/(5)`
`E_(2)=1.2`Volt