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Calculate the electrical conductivity ...

Calculate the electrical conductivity of the material of a conductor of length 3 m area of cross section `0.2mm^(2)` having a resistance of `2Omega` .

Text Solution

Verified by Experts

`l=3m`
`A=0.2mm^(2)=0.2xx10^(-6)m^(2)`
Now `R=rho(1)/(A)`
`P=(RA)/(l)`
Also , the conducitity of the wire `sigma=(1)/(P)`
`sigma=(l)/(RA)`
`=(3)/(2xx0.2xx10^(-6))`
`=7.5xx10^(6)Sm^(-1)`
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