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The vertices of a triangleABC are A(4,6)...

The vertices of a `triangleABC` are A(4,6), B(l,5) and C(7, 2). A line is drawn to intersect sides AB and AC at D andErespectively,such that `(AD)/(AB)=(AE)/(AC)=1/4`. Calculate the area of the `triangleADE` and compare it with the area of `triangleABC` .

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The correct Answer is:
`1:16`
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