BE and CF are two equal altitudes of a triangle ABC. Using RHS congruence rule, prove that the triangle ABC is isosceles.

In any triangle ABC : If (cosA)/a= (cosB)/b , prove that the triangle is isosceles.

If two medians of a triangle are equal, prove that the triangle is isosceles.

If altitudes from two vertices of a triangle to the opposite sides are equal prove that the triangle is isosceles.

In any triangle ABC : If a cos A = b cos B, prove that either the triangle is isosceles or right-angled.

If in triangle ABC, cot A + cot B + cot C = sqrt3 , prove that the triangle is equilateral.

ABC is a triangle in which BE and CF are perpendiculars to AC and AB respectively. If BE=CF, prove that triangleABC is isosceles.

Using which congruency rule given triangles are congruent ?

Prove that in any triangle ABC,c=a cos B+b cosA

ABC is a triangle in which altitudes BE and CF on sides AC and AB are equal that: ABAC, i.e. triangleABC is na isosceles triangle.

Prove analytically that the altitudes of a triangle are concurrent.