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A bullet of mass 10 g is fired with a ri...

A bullet of mass 10 g is fired with a rifle. The bullet takes 0.003 s to move through its barrel and leaves it with a velocity of 300 m/s. What is the force exerted on the bullet by the rifle ?

Text Solution

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Mass of bullet, m = 10 g
`=(10)/(1000)kg=0.01kg`
Intial velocity of the bullet, u = 0
Final velocity of the bullet with which it leaves the barrel 0of the gun, v = 300 m/s
Time taken, t = 0.003 s
Let acceleration of the bullet in the barrel = a
`therefore` Using `v=u+at` we have
`300=0+axx0.03=0.03a`
or `a=(300)/(0.03)m//s^2`
`=(300)/3xx1000=100000m//s^2`
Let force exerted by the rifle on the bullet = F
`therefore` Using F = ma, we get
`F=0.01xx100000N`
`=1/(100)xx100000N`
=1000 N
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