If A, B and C are the vertices of a triangle ABC, then what is the value of `vec(AB) + vec(BC) + vec(CA)` ?

If A, B, C are the vertices of a triangle whose position vectors are vec a, vec b, vec c and G is the centroid of the triangle ABC, then vec GA + vec GB + vec GC =

If vec a, vec b, vec c, vec d are the vertices of a square then

Let O, O' and G be the circumcentre, orthocentre and centroid of a Delta ABC and S be any point in the plane of the triangle. Statement -1: vec(O'A) + vec(O'B) + vec(O'C)=2vec(O'O) Statement -2: vec(SA) + vec(SB) + vec(SC) = 3 vec(SG)

If G is the centroid of Delta ABC and G' is the centroid of Delta A' B' C' " then " vec(A A)' + vec(B B)' + vec(C C)' =

If vec a ,\ vec b ,\ vec c be the vectors represented by the sides of a triangle, taken in order, then prove that vec a+ vec b+ vec c= vec0dot

If vec a, vec b, vec c are unit vectors such that vec a + vec b + vec c = vec 0 , then the value of vec a . vec b + vec b.vec c + vec c vec a is equal to

If A, B, C and D aare four points and vec AB = vec DC then vec AC + vec BD =

(vec b xx vec c) xx (vec c xx vec a ) =

If two vectors |vec(a)| = 2, |vec(b)| = 1 and vec(a).vec(b) = 1 , then find the value of (3vec(a) - 5vec(b)).(2vec(a) + 7vec(b)) .