If y = x^(log x) , then (dy)/(dx)equals...

If `y = x^(log x) `, then `(dy)/(dx)`equals

A

`logx x^(logx-1)`

B

`x^(logx-1)*2logx`

C

`xlog(logx)`

D

`1/(xlogx)*x^(logx-1)`.

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