If y=(x cot^3x)^(3/2), then dy/dx=...

If `y=(x cot^3x)^(3/2)`, then `dy/dx=`

A

`3/2(xcot^3x)^(1/2)(cot^3x-3xcot^2xcosec^2x)`

B

`3/2(xcot^3x)^(1/2)(cot^2x-3xcot^2xcosec^2x)`

C

`3/2(xcot^3x)^(1/3)(cot^3x-3xcosec^2x)`

D

`3/2(xcot^3x)^(3/2)(cot^3x-3xcosec^2x)`.

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