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A compound (60 gm) on analysis gave C = ...

A compound (60 gm) on analysis gave C = 24 gm, H = 4 gm, and O = 32 gm. Its empirical formula is:

A

`C_2H_2O`

B

`C_2H_4O_2`

C

`CH_2O`

D

`CH_2O_2`

Text Solution

Verified by Experts

The correct Answer is:
C
`{:(C,:,H,:,O),(24/21,:,4/1,:,32/16),(2,:,4,:,2):}`
Empirical Formula `=CH_2O`
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