In duma's method of estimation of nitrogen, 0.25 g of an organic compound gave 40 mL of nitrogen collected at 300 K temperature and 725 mm pressure. If the aqueous tension at 300 K is 25 mm, the percentage of nitrogen in the compound is

Options

A. 16.76
B. 15.76
C. 17.36
D. `18.20`

Answer

A

Explanation

`V_1 =40 mL , V_2`at NTP = ?
`P_(1) = 725 - 25= 700 mm , P_2 = 760 mm, " "T_(1) = 300 K,T_2 = 273 K`
`:. V_2 = (P_1V_1T_2)/(P_2T_1)= (700xx40xx273)/(760xx300)=33.52 mL, %N = 28/22400xx(33.52)/(0.25) xx100=16.76`